what is the removable DISCONTINUITIES of each:
y=\frac{4}{x+2}+1
The removable discontinuities of the function y = (4/(x+2)) + 1 occur when the denominator, x+2, equals zero.
To find these values, we set x+2 = 0 and solve for x:
x + 2 = 0
x = -2
Therefore, x = -2 is the removable discontinuity of the function y = (4/(x+2)) + 1.