A line passes through the points (-2,10) and (4,-10) write its equation in slope intercept form
To find the equation of the line in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the given points (-2, 10) and (4, -10) into the formula:
m = (-10 - 10) / (4 - (-2))
m = (-20) / 6
m = -10/3
Now we have the slope (m) of the line. Next, let's find the y-intercept (b).
Using the slope-intercept form (y = mx + b), we can substitute one of the given points into the equation to find the value of b. Let's use the point (-2, 10):
10 = (-10/3)(-2) + b
10 = 20/3 + b
To get b alone, we need to subtract 20/3 from both sides of the equation:
10 - 20/3 = b
30/3 - 20/3 = b
10/3 = b
Now we have the slope (m = -10/3) and the y-intercept (b = 10/3), so we can write the equation of the line in slope-intercept form:
y = (-10/3)x + (10/3)