A line passes through the points (-8,9) and (-2,-9) write its equation in slope intercept form
To write the equation of a line in slope-intercept form, we need to find the slope and the y-intercept.
First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (-8,9) and (-2,-9), we have:
m = (-9 - 9) / (-2 - (-8))
m = (-9 - 9) / (-2 + 8)
m = (-9 - 9) / (-2 + 8)
m = (-18) / 6
m = -3
Now that we have the slope, let's find the y-intercept (b) by substituting the values of one of the points into the slope-intercept form, y = mx + b.
Using the point (-8,9), we have:
9 = -3(-8) + b
9 = 24 + b
b = 9 - 24
b = -15
So the equation of the line in slope-intercept form is:
y = -3x - 15