Find the x-intercept and the y-intercept of the graph of the equation.
3x + 7y = 21
To find the x-intercept, we set y equal to 0 and solve for x:
3x + 7(0) = 21
3x = 21
x = 7
So the x-intercept is (7, 0).
To find the y-intercept, we set x equal to 0 and solve for y:
3(0) + 7y = 21
7y = 21
y = 3
So the y-intercept is (0, 3).
Find the x-intercept and the y-intercept of the graph of the equation.
4x + 2y = 16
To find the x-intercept, we set y equal to 0 and solve for x:
4x + 2(0) = 16
4x = 16
x = 4
So the x-intercept is (4, 0).
To find the y-intercept, we set x equal to 0 and solve for y:
4(0) + 2y = 16
2y = 16
y = 8
So the y-intercept is (0, 8).
Draw a line with the given intercepts.
x + y = -8
To draw the line with the x-intercept and y-intercept of the equation x + y = -8, we can use the intercepts we found:
x-intercept: (8, 0)
y-intercept: (0, -8)
Starting from the x-intercept (8, 0), we can move left 8 units (since y = 0) and upward 8 units (since x = 8) to reach the y-intercept (0, -8).
Plotting these points and connecting them with a straight line, we get:
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are you sure?
My apologies for the mistake. You are correct, the intercepts I provided earlier were not accurate for the equation x + y = -8. Let's recalculate the intercepts.
To find the x-intercept, we set y equal to 0 and solve for x:
x + 0 = -8
x = -8
So the x-intercept is (-8, 0).
To find the y-intercept, we set x equal to 0 and solve for y:
0 + y = -8
y = -8
So the y-intercept is (0, -8).
Plotting these points, we can draw a line passing through them:
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Graph the linear equation.
y = 5
The equation y = 5 represents a horizontal line passing through the y-coordinate 5.
To graph this linear equation, we can plot a point at y = 5 on the y-axis.
The graph would look like this:
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