Eric is solving the inequality 9x + 15 ≥
51 and graphing the solution. Which of the following describe the steps he should take using inverse operations to solve? (1 point)
Responses
Subtract 15 from both sides of the inequality and then multiply both sides of the inequality by 9.
Subtract 15 from both sides of the inequality and then multiply both sides of the inequality by 9.
Subtract 15 from both sides of the inequality and then divide both sides of the inequality by 9.
Subtract 15 from both sides of the inequality and then divide both sides of the inequality by 9.
Divide both sides of the inequality by 9 and then add 15 to both sides of the inequality.
Divide both sides of the inequality by 9 and then add 15 to both sides of the inequality.
Divide both sides of the inequality by 9 and then subtract 15 from both sides of the inequality.
Divide both sides of the inequality by 9 and then subtract 15 from both sides of the inequality.
Question 2
Help Eric draw his answer on the number line by selecting the correct responses below.
(2 points)
Eric would plot the point given in the solution on the number line with a(n)
circle and shade to the
right
of the point on the number line.
To solve the inequality 9x + 15 ≥ 51, Eric should take the following steps:
1. Subtract 15 from both sides of the inequality to isolate the term with the variable on one side.
9x + 15 - 15 ≥ 51 - 15
9x ≥ 36
2. Then, divide both sides of the inequality by 9 to solve for x.
9x/9 ≥ 36/9
x ≥ 4
So the correct steps Eric should take are: Subtract 15 from both sides of the inequality and then divide both sides of the inequality by 9.
For question 2, to graph the solution on a number line, Eric should:
1. Plot the point given in the solution, which is x = 4, on the number line.
2. Since the inequality is "greater than or equal to," Eric should use a closed circle to indicate that the point x = 4 is included in the solution set.
3. Shade to the right of the point on the number line, because the solution includes all numbers greater than or equal to 4.
Therefore, Eric would plot the point given in the solution on the number line with a closed circle and shade to the right of the point on the number line.