2x + 7 ≥ 27 or 3 + 3x ≤ 30
Responses
A 10 ≤ x ≤ 910 ≤ x ≤ 9
B x ≥ 10 or x ≤ 9x ≥ 10 or x ≤ 9
C x ≥ 17 or x ≤ 11x ≥ 17 or x ≤ 11
D x ≤ −10 or x ≤ 9
Let's solve each inequality separately and then combine our solutions.
For the first inequality:
2x + 7 ≥ 27
Subtract 7 from both sides:
2x ≥ 20
Divide both sides by 2:
x ≥ 10
For the second inequality:
3 + 3x ≤ 30
Subtract 3 from both sides:
3x ≤ 27
Divide both sides by 3:
x ≤ 9
Now, we combine these solutions using the "or," which means that any value of x that satisfies either inequality is valid:
x ≥ 10 or x ≤ 9
Therefore, the correct answer is:
B. x ≥ 10 or x ≤ 9