Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3
visits were reflected in their logbook during this two-week period, while only about 5×10^2
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number
To determine how many times higher the number of library visits before the examination day is compared to the library visits in an average week, we need to divide the total number of visits during the two-week period leading up to the exams by the number of visits in an average week.
During the two-week period before exams, there were approximately:
2 × 10^3 visits
And in an average week, there are about:
5 × 10^2 visits
Now, because the 2 × 10^3 visits are over a two-week period, we should calculate the average number of visits per week during this period by dividing this number by 2.
Average visits per week (before exams) = (2 × 10^3) / 2
Average visits per week (before exams) = 1 × 10^3 visits per week
Now we need to divide this average number of weekly visits before exams by the number of visits in an average week to find out how many times higher it is.
Times higher = (1 × 10^3) / (5 × 10^2)
Since 10^3 = 10^2 × 10, we can simplify this as:
Times higher = (10 × 5 × 10^2) / (5 × 10^2)
The 5 × 10^2 terms cancel each other out, and we're left with:
Times higher = 10
Thus, the number of library visits before examination day is 10 times higher compared to the library visits in an average week.