What is the solution of the proportion? (1 point) Responses 24 24 8 8 Image with alt text: fraction
It seems there is a mistake in the question, as it is unclear what proportion you are referring to. However, if you are looking for a solution to a proportion given by the format "24/24 = 8/8" (which the text seems to imply), then this proportion is already in its simplest form.
In the given example, both sides of the equation (24/24 and 8/8) are equal to 1. This is because any number divided by itself is equal to 1. The proportion is therefore true and balanced as is.
If there's a different proportion you're asking about, or if you need the solution for a variable within a proportion, please provide the full proportion with the missing value, and I'll be happy to help you solve it.
the portportion: 3/4=m/32
To solve the proportion \( \frac{3}{4} = \frac{m}{32} \), you can use cross-multiplication.
Cross-multiplication involves multiplying the numerator of one fraction by the denominator of the other fraction and setting the two products equal to each other:
\( 3 \times 32 = 4 \times m \)
Now solve for \( m \):
\( 96 = 4m \)
To find \( m \), divide both sides of the equation by 4:
\( \frac{96}{4} = m \)
\( m = 24 \)
So, the solution to the proportion \( \frac{3}{4} = \frac{m}{32} \) is \( m = 24 \).
what is the geometric mean of 99 and 11?
The geometric mean of two numbers is the square root of the product of those two numbers. To find the geometric mean of 99 and 11, you multiply them together and then take the square root of the result.
The product of 99 and 11 is:
\( 99 \times 11 = 1089 \)
Now, take the square root of 1089:
\( \sqrt{1089} = 33 \)
The geometric mean of 99 and 11 is 33.
eaht is the geomtric mean 0f 5000 89?
To find the geometric mean of the numbers 5000 and 89, you would use the same process as before; multiply the two numbers together and take the square root of the product.
The product of 5000 and 89 is:
\( 5000 \times 89 = 445000 \)
Now, take the square root of 445000:
\( \sqrt{445000} \)
Calculating this gives:
\( \sqrt{445000} \approx 667.224 \)
So, the geometric mean of 5000 and 89 is approximately 667.224.
ABC has side lengths 8, 15, and 17. Do the side lengths form a Pythagorean triple? (1 point) Responses yes yes no
A Pythagorean triple consists of three positive integers a, b, and c, such that \( a^2 + b^2 = c^2 \). This equation corresponds to the Pythagorean theorem for a right-angled triangle, where a and b represent the lengths of the legs and c represents the length of the hypotenuse.
Let's check if the side lengths 8, 15, and 17 form a Pythagorean triple:
\( 8^2 = 64 \)
\( 15^2 = 225 \)
\( 17^2 = 289 \)
Now, add the squares of the smaller side lengths (8 and 15) to see if they equal the square of the largest side length (17):
\( 64 + 225 = 289 \)
\( 289 = 289 \)
Since \( 64 + 225 \) equals \( 289 \), and \( 289 \) is also equal to \( 17^2 \), the side lengths 8, 15, and 17 do indeed form a Pythagorean triple. This means that a triangle with these side lengths would be a right triangle with the sides 8 and 15 forming the legs, and 17 as the hypotenuse.
Therefore, the response is "yes." The side lengths form a Pythagorean triple.