given l = 30 in w = 20 in h = 18 in, and x = 36.1 in find the length of d round the answer to the nearest tenth.
To find the length of \(d\), which I assume is the diagonal of a rectangular box, you would use the 3D version of the Pythagorean theorem. This formula states:
\(d = \sqrt{l^2 + w^2 + h^2}\)
where \(l\), \(w\), and \(h\) are the length, width, and height of the box, respectively.
Given \(l = 30\) inches, \(w = 20\) inches, and \(h = 18\) inches, the diagonal \(d\) can be calculated as:
\(d = \sqrt{30^2 + 20^2 + 18^2}\)
\(d = \sqrt{900 + 400 + 324}\)
\(d = \sqrt{1624}\)
\(d \approx 40.3\) inches
So, the length of the diagonal \(d\) is approximately \(40.3\) inches, when rounded to the nearest tenth.