A rental car company charges $26.03 per day to rent a car and $0.13 for every mile driven. Malik wants to rent a car, knowing that:
He plans to drive 250 miles.
He has at most $350 to spend.
Which inequality can be used to determine dd, the maximum number of days Malik can afford to rent for while staying within his budget?
26.03d+32.5≥350
26, point, 0, 3, left bracket, 32, point, 5, plus, d, right bracket, is greater than or equal to, 35026.03(32.5+d)≥350
26, point, 0, 3, d, plus, 32, point, 5, is less than or equal to, 35026.03d+32.5≤350
26, point, 0, 3, left bracket, 32, point, 5, plus, d, right bracket, is less than or equal to, 35026.03(32.5+d)≤350
To determine the maximum number of days Malik can afford to rent a car for while staying within his budget, we have to set up an inequality that represents the cost of renting the car per day and the cost for miles driven not exceeding $350.
Each day Malik rents the car, it will cost him $26.03. So, for d days, the rental cost is $26.03 * d.
Now for the miles driven, since he plans to drive 250 miles, the cost for driving is $0.13 per mile. Therefore, the cost for driving 250 miles is $0.13 * 250.
Let's calculate that:
Cost for miles = $0.13 * 250 miles = $32.50
So, the total cost for renting the car for d days plus the cost for driving 250 miles should be less than or equal to $350. Our inequality should therefore add the daily rental cost (26.03d) to the cost for the miles ($32.50) and compare that to Malik's budget of $350:
26.03d + 32.50 ≤ 350
This is the correct inequality to use to determine d, the maximum number of days Malik can rent the car for while staying within his budget. So, the right choice would be:
26.03d + 32.5 ≤ 350