Cu62+(aq)+2e^- ---> Cu(s)
a.Cathode
b.Anode
a. Cathode (Cu62+(aq) + 2e^- ---> Cu(s)): This is the electrode where reduction occurs. Cu62+(aq) gains two electrons to form Cu(s).
b. Anode: This is the electrode where oxidation occurs. The oxidation half-reaction is missing in the given equation, so it is not specified.