Suppose a spider was able to create one thread that would extend from the top-right back corner of its tank to the bottom-left front corner. Approximately how long would that thread need to be for the tank below? The path of the spider's thread is shown with a red dotted line. Round your answer to the nearest tenth of an inch. (2 points) The diagonal of the bottom of the tank is (to the nearest tenth of an inch how many inches? To the nearest tenth of an inch, the length of the spider's thread is how many inches?
numbers are 32in,24in and 10in.
The tank has dimensions 32in, 24in, and 10in. To find the diagonal of the bottom of the tank, we can use the Pythagorean theorem.
Let's label the sides of the bottom of the tank as follows: the length (32in), the width (24in), and the diagonal (d).
Using the Pythagorean theorem, we have:
d^2 = 32^2 + 24^2
d^2 = 1024 + 576
d^2 = 1600
d = √1600
d ≈ 40in
So, the diagonal of the bottom of the tank is approximately 40 inches.
The spider's thread would need to extend from the top-right back corner to the bottom-left front corner. This is equivalent to the hypotenuse of a right triangle with sides measuring 32 inches and 10 inches.
Using the Pythagorean theorem, we have:
h^2 = 32^2 + 10^2
h^2 = 1024 + 100
h^2 = 1124
h ≈ √1124
h ≈ 33.5in
So, the length of the spider's thread would be approximately 33.5 inches.