A 160.8mL sample of NaCl(aq) is reacted in 44.5mL of 1.23mol/L KMnO4(aq). What is the concentration of NaCl?
To find the concentration of NaCl, we need to use the equation:
M1V1 = M2V2
Where:
- M1 is the concentration of NaCl
- V1 is the volume of NaCl
- M2 is the concentration of KMnO4
- V2 is the volume of KMnO4
Plugging in the given values:
M1(160.8mL) = (1.23mol/L)(44.5mL)
Divide both sides by 160.8mL:
M1 = (1.23mol/L)(44.5mL) / 160.8mL
M1 ≈ 0.3391 mol/L
Therefore, the concentration of NaCl is approximately 0.3391 mol/L.