Divide the polynomials using long division.
(81b^4-1)/(3b+1)
27b^3 - 27b^2 + 27b - 27
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3b + 1 | 81b^4 + 0b^3 + 0b^2 + 0b - 1
- (81b^4 + 27b^3)
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- 27b^3 + 0b^2 + 0b
+ 27b^3 + 9b^2
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- 9b^2 + 0b - 1
+ 9b^2 + 3b
_________________________
3b - 1
Therefore, the result of dividing (81b^4 - 1) by (3b + 1) using long division is:
27b^3 - 27b^2 + 27b - 27 with a remainder of 3b - 1.