Using the quadratic formula, find the solution to 3x^18x+24=0
To solve the quadratic equation 3x^2 + 18x + 24 = 0 using the quadratic formula, we first need to identify the values of a, b, and c in the equation ax^2 + bx + c = 0.
In this case, a = 3, b = 18, and c = 24.
The quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a).
Substituting the values, we have x = (-(18) ± √((18)^2 - 4(3)(24))) / (2(3)).
Simplifying further, we get x = (-18 ± √(324 - 288)) / 6.
Simplifying the square root, we have x = (-18 ± √36) / 6.
The square root of 36 is 6, so x = (-18 ± 6) / 6.
This gives two possible solutions:
1. x = (-18 + 6) / 6 = -12 / 6 = -2
2. x = (-18 - 6) / 6 = -24 / 6 = -4
Therefore, the solutions to the equation 3x^2 + 18x + 24 = 0 are x = -2 and x = -4.