A game spinner has regions that are numbered 1 through 8. If the spinner is used twice, what is the probability that the first number is a 3 and the second is a 6?
The total number of outcomes when the spinner is used twice is $8\cdot 8=64$. There is only 1 outcome where the first number is 3 and the second number is 6. So, the probability is $\dfrac{1}{64}$.
