What part of the coordinate plane is equidistant from the points A(-3,2) and B(3, 2)?
Explain your answer.
The points A(-3,2) and B(3,2) both have the same y-coordinate, which means they lie on the same horizontal line. The line connecting these two points is a horizontal line passing through the point (0,2).
To find the point that is equidistant from A(-3,2) and B(3,2), we need to find the point on this horizontal line that has the same x-coordinate as the midpoint of the line segment AB.
The midpoint of AB can be found by taking the average of the x-coordinates of A and B:
Midpoint = ( (x1 + x2) / 2 , y1 )
= ( (-3 + 3) / 2, 2 )
= ( 0, 2 )
Therefore, the point that is equidistant from A(-3,2) and B(3,2) is (0,2), which is on the horizontal line passing through the points A and B.