A baker needs to cover a cylinder cake with icing. The cake has a radius of 5 inches and a height of 7 inches. How many square inches of icing will be needed to cover the sides and top of the cake? icing will not be added to the bottom of the cake. Use 3.14 for p and round your answer to the nearest tenth. (point).
The surface area of the sides of the cylinder can be found by multiplying the circumference of the base by the height of the cylinder. The circumference is found using the formula C = 2πr, where r is the radius of the base of the cylinder.
C = 2π(5 inches) = 10π inches
So, the surface area of the sides of the cake is 10π(7 inches) = 70π square inches.
The surface area of the top of the cake is equal to the area of a circle with radius 5 inches, which is given by the formula A = πr^2.
A = π(5 inches)^2 = 25π square inches.
The total surface area of the sides and top of the cake is 70π + 25π = 95π square inches.
Using the approximation 3.14 for π, we have:
95π square inches ≈ 95(3.14) = 298.3 square inches.
Rounded to the nearest tenth, the baker will need approximately 298.3 square inches of icing to cover the sides and top of the cake.