The minor axis of an ellipse 9x2+4y2=36 is
The minor axis of an ellipse can be found by taking the square root of the larger denominator in the equation.
In this case, the larger denominator is 9x^2, so we need to find the square root of 9.
√9 = 3
Therefore, the minor axis of the ellipse 9x^2 + 4y^2 = 36 is 2 times 3, which is 6.