An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles.
To find the width of the art project, we need to determine the dimensions of the rectangle.
Let's assume the width of the rectangle is x inches and the length is y inches.
Since the top edge is labeled 10 inches, we can say that:
x + 2 = 10
Simplifying this equation, we find:
x = 10 - 2
x = 8
Now, we know that the area of a rectangle is given by:
Area = Length x Width
Given that the area of the art project is 63.6 square inches, we can set up the following equation:
63.6 = y * 8
Dividing both sides of the equation by 8, we find:
y = 63.6 / 8
y ≈ 7.95
Therefore, the width of the art project is approximately 8 inches.