Use the slope and y-intercept to graph the equation.
4y+12x=0
To graph the equation 4y + 12x = 0, we can start by solving for y in terms of x.
4y + 12x = 0
4y = -12x
y = (-12/4)x
y = -3x
Now that we have the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we can look at the coefficients and constants in the equation to determine these values.
The coefficient of x is 3, so the slope (m) is -3.
The constant term is 0, so the y-intercept (b) is 0.
Using this information, we can now plot the graph of the equation.
First, plot the y-intercept (0,0), which is the point where the line intersects the y-axis.
Next, use the slope to determine additional points on the line. The slope of -3 means that for every 1 unit increase in x, y decreases by 3 units.
Starting from the y-intercept (0,0), move 1 unit to the right (increase x by 1) and 3 units down (decrease y by 3), and plot that point. This gives us the point (1, -3).
Repeat this process to find another point. Starting from (1, -3), move 1 unit to the right (increase x by 1) and 3 units down (decrease y by 3), and plot that point. This gives us the point (2, -6).
Continue this pattern to find more points and plot them on the graph.
As you plot these points, you will notice that they lie in a straight line. Connect the points with a line to complete the graph.
The graph of the equation 4y + 12x = 0 is a straight line with a slope of -3 and goes through the origin (0,0).