math

soybean meal is 18% protein; cornmeal is 9% protein. how many pounds of each should be mixed together in order to get 360-lb mixture that is 14%
How many pounds of cornmeal should be in the mixture? 200
how many lbs of soybean meal should be in the mixture? 160
can someone tell me if I have this right?

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asked by jason
  1. let x = pounds of soybean meal
    let y = pounds of cornmeal

    There should be a total of 360 pounds. Therefore, x+y = 360

    The protein % is .14. Out of 360 pounds, that would be 360*.14 = 50.4

    Therefore, .18x + .09y = 50.4

    substitution:

    x=360-y

    .18(360-y) + .09y = 50.4
    64.8 - .18y + .09y = 50.4
    -.09y = -14.4
    y = 160

    x+y = 360
    x+160 = 360
    x = 200

    200 pounds of soybean meal
    160 pounds of cornmeal

    Checking my work:

    .18x + .09y = 50.4
    .18*200 + .09*160 = 50.4
    50.4 = 50.4

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    posted by Marth

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