Determine x values for which the tangent line is horizontal to the curve 16x-1-x^2=y
To find the values of x where the tangent line is horizontal, we need to find the points where the derivative of the curve is equal to zero.
First, let's find the derivative of the curve.
16x - 1 - x^2 = y
Differentiating both sides with respect to x:
16 - 2x = dy/dx
Now, set the derivative equal to zero:
16 - 2x = 0
2x = 16
x = 8
So, the tangent line is horizontal to the curve at x = 8.