An infinite number line labeled from negative 2 to 10, has tick marks in increments of 1. A shaded region exists to the right of a left parenthesis at 0 and the left of a right bracket between 6 and 7 labeled StartFraction 13 Over 2 EndFraction.
-2-1012345678910
13 divided by 2
Write the solution in interval notation.
(Type your answer in interval notation. Use integers or fractions for any numbers in the expression.)
The shaded region exists between 0 and 6, since the left parenthesis at 0 is not included and the right bracket between 6 and 7 is not included as well.
So, the solution in interval notation is: (0, 6)
no
Apologies for the mistake.
The shaded region exists to the right of 0 and to the left of StartFraction 13 Over 2 EndFraction.
In interval notation, this can be written as:
(0, 13/2)
noo
I apologize for the confusion.
The shaded region exists to the right of 0 and to the left of StartFraction 13 Over 2 EndFraction.
In interval notation, this can be written as:
(0, 6.5)
To write the solution in interval notation, we need to indicate the range of values that fulfill the given conditions.
The shaded region exists to the right of a left parenthesis at 0 and to the left of a right bracket between 6 and 7, labeled StartFraction 13 Over 2 EndFraction.
Let's break it down step by step:
1. The shaded region exists to the right of a left parenthesis at 0.
This means that any value greater than 0 should be included in the solution. We can represent this by using the interval notation (0, ∞).
2. The shaded region exists to the left of a right bracket between 6 and 7, labeled StartFraction 13 Over 2 EndFraction.
To determine the range between 6 and 7, we need to find the midpoint.
The midpoint between 6 and 7 is calculated as:
(Midpoint) = (6 + 7) / 2 = 13 / 2
So, the shaded region exists to the left of the right bracket at 13/2. We can represent this by using the interval notation (-∞, 13/2).
Bringing both parts together, the solution in interval notation is:
(0, 13/2)