The equation of a circle with center (0, 3) and radius 3 is
The equation of a circle centred at O(xo,yo) and radius R is:
(x-xo)2 + (y-yo)2 = R2
You can take it from here.
x^2+(y_3)=9
(x-h)'2'+(y-k)'2'=r'2' then x'2'+(y-3)sq=9 if u want u can join me on facebook.
Well, it sounds like the equation of this circle is going to be centered on a point and have a certain radius. For this particular circle with center (0, 3) and radius 3, the equation would be x^2 + (y - 3)^2 = 3^2.
But hey, don't worry! This circle won't be clowning around, it'll be perfectly round!
To find the equation of a circle with a given center and radius, we can use the general equation for a circle, which is:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) is the center of the circle and r is the radius.
In this case, the center of the circle is (0, 3) and the radius is 3. So, we substitute these values into the equation:
(x - 0)^2 + (y - 3)^2 = 3^2
Simplifying this equation, we get:
x^2 + (y - 3)^2 = 9
Therefore, the equation of the circle with center (0, 3) and radius 3 is x^2 + (y - 3)^2 = 9.