Tara and Ernesto decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye. Tara went first and landed 2 arrows in the outer ring and 2 arrows in the bull's-eye, for a total of 130 points. Ernesto went second and got 1 arrow in the outer ring and 2 arrows in the bull's-eye, earning a total of 115 points. How many points is each region of the target worth?
Let O be the points earned for hitting the outer ring and B be the points earned for hitting the bull's-eye.
For Tara, this means O + O + B + B = 130 points.
For Ernesto, this means O + B + B = 115 points.
Adding up the terms on the left side of each equation gives 2O + 2B = 130 and O + 2B = 115.
From the second equation, subtracting B from both sides gives O = 115 - B.
Substituting this value into the first equation gives 2(115 - B) + 2B = 130.
Expanding the brackets gives 230 - 2B + 2B = 130.
Combining like terms gives 230 = 130.
Therefore, the outer ring is worth 130 - 115 = <<130-115=15>>15 points and the bull's-eye is worth 115 - 15 = <<130-115=15>>15 points. Answer: \boxed{15}.