Which equation is in the equation of a line that passes through (-10,3) and is perpendicular to y = 5x - 7?
A. y = 5x + 53
B. y = 1/5x - 7
C. y = 1/5x + 1
D. y = 1/5x + 5
The slope of the line y = 5x - 7 is 5, since the coefficient of x is the slope. The equation of a line perpendicular to y = 5x - 7 will have a slope that is the negative reciprocal of 5, which is -1/5.
We can find the y-intercept of the line by plugging the coordinates of the point (-10,3) into the equation y = mx + b and solving for b.
3 = -1/5(-10) + b
3 = 2 + b
b = 1
Therefore, the equation of the line that passes through (-10,3) and is perpendicular to y = 5x - 7 is y = -1/5x + 1.
So, the correct option is C. y = 1/5x + 1.