Trend Lines Quick Check
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Question
Use the image to answer the question.
An illustration of a scatterplot shows x on x-axis from 65 to 75 in increments of 1 and y on the y-axis from 200 to 240 in increments of 2.5. Eleven points are plotted. The approximate plotted points are as follows: left parenthesis 65 comma 205 right parenthesis, left parenthesis 67 comma 216 right parenthesis, left parenthesis 68 comma 210 right parenthesis, left parenthesis 68 comma 218 right parenthesis, left parenthesis 69 comma 224 right parenthesis, left parenthesis 70 comma 220 right parenthesis, left parenthesis 70 comma 224 right parenthesis, left parenthesis 71 comma 230 right parenthesis, left parenthesis 72 comma 235 right parenthesis, left parenthesis 74 comma 200 right parenthesis, and left parenthesis 74 comma 240 right parenthesis.
Is there a relationship between the two sets of data? How do you know?
(1 point)
Responses
No, because the data points are not close to the trend line.
No, because the data points are not close to the trend line.
Yes, because the data points are not close to the trend line.
Yes, because the data points are not close to the trend line.
Yes, because the data points are close to the trend line.
Yes, because the data points are close to the trend line.
No, because the data points are close to the trend line.
No, because the data points are close to the trend line.
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you sure???
Use the image to answer the question.
An illustration of a scatterplot shows x on x-axis from 65 to 75 in increments of 1 and y on the y-axis from 200 to 240 in increments of 2.5. Eleven points are plotted. The approximate plotted points are as follows: left parenthesis 65 comma 205 right parenthesis, left parenthesis 67 comma 216 right parenthesis, left parenthesis 68 comma 210 right parenthesis, left parenthesis 68 comma 218 right parenthesis, left parenthesis 69 comma 224 right parenthesis, left parenthesis 70 comma 220 right parenthesis, left parenthesis 70 comma 224 right parenthesis, left parenthesis 71 comma 230 right parenthesis, left parenthesis 72 comma 235 right parenthesis, left parenthesis 74 comma 200 right parenthesis, and left parenthesis 74 comma 240 right parenthesis.
Are there any outliers in the data shown on the scatterplot? If so, where?
(1 point)
Responses
Yes, at (65, 205)
Yes, at left parenthesis 65 comma 205 right parenthesis
No, there are no outliers in the data.
No, there are no outliers in the data.
Yes, at (74, 200)
Yes, at left parenthesis 74 comma 200 right parenthesis
Yes, at (74, 240)
Yes, there are outliers in the data shown on the scatterplot. The outliers are at (65, 205) and (74, 240).
are you suree??
I apologize for the confusion. Based on the given data, there are no outliers in the scatterplot.
to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 10 in increments of 1. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 9 right parenthesis, left parenthesis 4 comma 8 right parenthesis, left parenthesis 8 comma 7 right parenthesis, and left parenthesis 10 comma 6.5 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
Responses
y=−14x
y equals negative Start Fraction 1 over 4 End Fraction x
y=1x+9
y equals 1 x plus 9
y=−58x+9
y equals negative Start Fraction 5 over 8 End Fraction x plus 9
y=−14x+9
y equals negative Start Fraction 1 over 4 End Fraction x plus 9
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page 21 of 21
To write an equation in slope-intercept form of the trend line, we need to determine the slope and the y-intercept. Looking at the given points (0, 9), (4, 8), (8, 7), and (10, 6.5), we can calculate the slope using the formula:
slope (m) = (change in y) / (change in x)
Using the points (0, 9) and (10, 6.5):
slope (m) = (6.5 - 9) / (10 - 0) = -2.5 / 10 = -0.25
Now that we have the slope, we can write the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. To find the y-intercept, we can substitute one of the given points into the equation and solve for b. Let's use the point (0, 9):
9 = -0.25(0) + b
9 = b
So the y-intercept (b) is 9.
Now we can write the equation:
y = -0.25x + 9
Therefore, the correct equation in slope-intercept form of the trend line is y = -0.25x + 9.
Use the image to answer the question.
A scatterplot graph shows x-axis ranging from 0 to 100 and y-axis ranging from 0 to 50. Both axes are drawn in increments of 5 but labeled in increments of 10. Multiple points are plotted around a line that points upward to the right.
The line passes through left parenthesis 0 comma 30 right parenthesis, left parenthesis 15 comma 40 right parenthesis, and left parenthesis 30 comma 50 right parenthesis. 14 points are plotted close to or on the line. The line has an arrowhead on the top of it.
Write an equation in slope-intercept form of the trend line.
(1 point)
Responses
y=23x+40
y equals Start Fraction 2 over 3 End Fraction x plus 40
y=−23x+30
y equals negative Start Fraction 2 over 3 End Fraction x plus 30
y=23x+30
y equals Start Fraction 2 over 3 End Fraction x plus 30
y=34x+30
y equals Start Fraction 3 over 4 End Fraction x plus 30
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page 21 of 21
To write an equation in slope-intercept form of the trend line, we need to determine the slope and the y-intercept. Looking at the given points (0, 30), (15, 40), and (30, 50), we can calculate the slope using the formula:
slope (m) = (change in y) / (change in x)
Using the points (0, 30) and (30, 50):
slope (m) = (50 - 30) / (30 - 0) = 20 / 30
Simplifying:
slope (m) = 2/3
Now that we have the slope, we can write the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. To find the y-intercept, we can substitute one of the given points into the equation and solve for b. Let's use the point (0, 30):
30 = (2/3)(0) + b
30 = b
So the y-intercept (b) is 30.
Now we can write the equation:
y = (2/3)x + 30
Therefore, the correct equation in slope-intercept form of the trend line is y = (2/3)x + 30.