The equilibrium constant has been determined in several reactions as follows:
1. N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^–31
2. H2(g) + Cl2(g) ⇔ 2HCl (g) Keq = 4.0 x 10^31
3. 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4. Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
The correct arrangement of the above reactions, in decreasing order of their ability to form products, is ________, ________, ________, and ________.
a) 1, 2, 4, 3
b) 1, 4, 3, 2
c) 2, 1, 3, 4
d) 2, 3, 4, 1
e) 3, 4, 2, 1
To determine the decreasing order of the ability to form products, we can look at the magnitude of the equilibrium constant (Keq) for each reaction. The larger the Keq, the greater the amount of products formed.
From largest to smallest Keq:
1) 2, 3, 4, 1
Therefore, the correct arrangement is c) 2, 1, 3, 4.
are you sure?
Apologies for the confusion. Let's analyze the given equilibrium constants again:
1) N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^–31
2) H2(g) + Cl2(g) ⇔ 2HCl(g) Keq = 4.0 x 10^31
3) 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4) Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
Now, let's arrange them in decreasing order of their ability to form products:
1) 2, 1, 3, 4
Therefore, the correct arrangement is c) 2, 1, 3, 4.
To determine the correct arrangement of the reactions in decreasing order of their ability to form products, we need to consider the magnitude of the equilibrium constants.
The equilibrium constant (Keq) measures the extent to which a reaction proceeds to the products side at equilibrium. A larger Keq indicates a higher concentration of products compared to reactants, meaning the reaction favors the formation of products.
In this case, we can simply compare the magnitudes of the given Keq values to determine the order.
Starting with the highest Keq value:
1. H2(g) + Cl2(g) ⇔ 2HCl(g) Keq = 4.0 x 10^31
2. Cu(s) + 2Ag+(aq) ⇔ Cu2+(aq) + 2Ag(s) Keq = 2.0 x 10^15
3. 2CO(g) + O2(g) ⇔ 2CO2(g) Keq = 2.3 x 10^22
4. N2(g) + O2(g) ⇔ 2NO(g) Keq = 4.8 x 10^-31
Therefore, arranging them in decreasing order, the correct answer is:
c) 2, 1, 3, 4