In Miss Bennett’s daycare, she has 240 crayons and 45 pieces of construction paper. Find the largest number of children possible so that everyone has an equal number of crayons and paper.(1 point)
To find the largest number of children who can have an equal number of crayons and construction paper, we need to find the greatest common divisor (GCD) of 240 and 45.
The prime factorization of 240 is 2^4 * 3 * 5.
The prime factorization of 45 is 3^2 * 5.
To find the GCD, we take the highest power of each common prime factor. In this case, the highest power of 3 is 3, and the highest power of 5 is 1.
Therefore, the GCD of 240 and 45 is 3 * 5 = 15.
So, the largest number of children who can have an equal number of crayons and construction paper is 15.