answer the question.
A square pyramid is shown. Its height is shown with a dotted line labeled 321 feet. Its slant height is shown with a dotted line labeled 436.5 feet. The variable l is shown along one of the edges of the square base.
The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth.
(1 point)
ft.
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To find the length of the edge of the square base, we can use the Pythagorean theorem. The slant height, the height, and one side of the square base form a right triangle.
Let's call the length of the edge of the square base l. The slant height is 436.5 ft and the height is 321 ft.
Using the Pythagorean theorem, we have:
l^2 + 321^2 = 436.5^2
l^2 + 103041 = 190622.25
l^2 = 190622.25 - 103041
l^2 = 87581.25
Taking the square root of both sides, we get:
l ≈ √87581.25
l ≈ 295.7 ft
Therefore, the length of the edge of the square base is approximately 295.7 ft.
nope
I apologize for the mistake.
To find the length of the edge of the square base, we can use the relationship between the slant height, height, and edge length of a square pyramid.
Let's call the length of the edge of the square base l. The slant height is 436.5 ft and the height is 321 ft.
We can use the Pythagorean theorem to relate these measurements:
l^2 = (height)^2 + (slant height)^2
l^2 = 321^2 + 436.5^2
l^2 = 103041 + 190738.25
l^2 = 293779.25
Taking the square root of both sides, we get:
l ≈ √293779.25
l ≈ 542.1 ft.
Therefore, the length of the edge of the square base is approximately 542.1 ft.
nah
Apologies for the earlier incorrect response.
To find the length of the edge of the square base, we can use the Pythagorean theorem.
Let's call the length of the edge of the square base l. The slant height is 436.5 ft and the height is 321 ft.
Using the Pythagorean theorem, we have:
l^2 = (slant height)^2 - (height)^2
l^2 = 436.5^2 - 321^2
l^2 = 190622.25 - 103041
l^2 = 87581.25
Taking the square root of both sides, we get:
l ≈ √87581.25
l ≈ 295.6 ft
Therefore, the length of the edge of the square base is approximately 295.6 ft.
not it
Apologies for the confusion. Let's try again.
To find the length of the edge of the square base, we can use the relationship between the slant height, height, and edge length of a square pyramid.
Let's call the length of the edge of the square base l. The slant height is 436.5 ft and the height is 321 ft.
We can use the Pythagorean theorem to relate these measurements:
l^2 = (slant height)^2 - (height)^2
l^2 = 436.5^2 - 321^2
l^2 = 190622.25 - 103041
l^2 = 87611.25
Taking the square root of both sides, we get:
l ≈ √87611.25
l ≈ 296.5 ft
Therefore, the length of the edge of the square base is approximately 296.5 ft.
ell nah
I apologize for the repeated incorrect responses. Let's try again.
To find the length of the edge of the square base, we can use the relationship between the slant height, height, and edge length of a square pyramid.
Using the Pythagorean theorem, we have:
(edge length)^2 = (slant height)^2 - (height)^2
l^2 = 436.5^2 - 321^2
l^2 = 190622.25 - 103041
l^2 = 87581.25
l ≈ 296.03 ft
Therefore, the length of the edge of the square base is approximately 296.0 ft, rounded to the nearest tenth.