2 pounds of feeling large fads of licked at 1 VAT is empty, and the pump is filling at a rate of 6 gallons per minute. The other vet already contains 28 gallons of his continuative fill out a rate of 4 gallons per minute. When will the 2 fats have the same amount of liquid?
To solve this problem, let's denote the time it takes for the two vats to have the same amount of liquid as "t" minutes.
For the first vat, which initially contains 2 pounds (or gallons) of liquid, the rate at which it is being filled is 6 gallons per minute. Therefore, after t minutes, it will contain 2 + 6t gallons.
For the second vat, which initially contains 28 gallons of liquid, the rate at which it is being filled is 4 gallons per minute. Therefore, after t minutes, it will contain 28 + 4t gallons.
To find when the two vats have the same amount of liquid, we can set the expressions for the amount of liquid in each vat equal to each other and solve for t:
2 + 6t = 28 + 4t
Subtract 4t from both sides:
2t = 26
Divide both sides by 2:
t = 13
Therefore, the two vats will have the same amount of liquid after 13 minutes.