16x^2+9=0
A -3/4i, 3/4i
B -4/3i, 4/3i
C -3/4, 3/4
D -9/16i, 9/16i
To solve the quadratic equation 16x^2 + 9 = 0, we can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 16, b = 0, and c = 9. Plugging these values into the quadratic formula, we get:
x = (0 ± √(0^2 - 4(16)(9))) / (2(16))
= (0 ± √(-576)) / 32
= (0 ± √(-1) √(576)) / 32
= (0 ± i√576) / 32
= (0 ± 24i) / 32
= 0 ± 3i/4
So the solutions to the quadratic equation 16x^2 + 9 = 0 are:
x = -3i/4 and x = 3i/4
Therefore, the correct answer is A) -3/4i, 3/4i.