Use the image to answer the question.
A coordinate plane plots temperature in Celsius for different days. The x-axis labeled day, and the y-axis labeled temperature degree Celcius, both range from negative 5 to 5 in increments of 1. Six unlabeled points are plotted. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. Points are plotted at left parenthesis 2 comma 2 right parenthesis; left parenthesis negative 4 comma 4 right parenthesis, left parenthesis negative 3 comma 0 right parenthesis; left parenthesis negative 2 comma negative 2 right parenthesis; left parenthesis zero comma zero right parenthesis; left parenthesis 4 comma negative 1 right parenthesis.
Alex is tracking temperatures. Today the temperature was 0° Celsius, which is represented by the point (0, 0). If the temperature yesterday was right in between today’s temperature and the temperature two days ago, what was the temperature yesterday?
To find the temperature yesterday, we need to find the point that lies right in between the point representing today's temperature and the point representing the temperature two days ago on the coordinate plane.
From the given points, we can see that the temperature two days ago is represented by the point (-2, -2) and today's temperature is represented by the point (0, 0).
To find the point that lies right in between these two points, we can find the average of the x-coordinates and the average of the y-coordinates.
The average of the x-coordinates is (-2 + 0)/2 = -1.
The average of the y-coordinates is (-2 + 0)/2 = -1.
Therefore, the point representing the temperature yesterday is (-1, -1).
So, the temperature yesterday was -1° Celsius.