Given that R= 0.0821(L⋅atm) / (mol⋅K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K?

Question

Given that R= 0.0821(L⋅atm) / (mol⋅K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K?

This is what I have so far, Fill in the blank spots please.

P= 1.8 atm
V= 2L
Answer this: N= ____ ?
R=.0821 L atm/ mol * k
T=270 K

PV=N= (1.8)(2)/ (0.821)(270)

Answer this: RT=______ ?

Answer 1

RT= (0.0821)(270) = 22.167

Now, plug in the values into the equation PV=N:

N = (1.8)(2)/(22.167)

N ≈ 0.162 moles