Given that R= 0.0821(L⋅atm) / (mol⋅K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K?
This is what I have so far, Fill in the blank spots please.
P= 1.8 atm
V= 2L
N= ____ ?
R=.0821 L atm/ mol * k
T=270 K
PV=N= (1.8)(2)/ (0.821)(270)
RT=______ ?
To find the number of moles (N), you can rearrange the ideal gas equation PV = nRT to solve for N.
The equation becomes:
N = (PV) / (RT)
Plugging in the given values:
P = 1.8 atm
V = 2 L
R = 0.0821 L⋅atm / (mol⋅K)
T = 270 K
N = (1.8 atm * 2 L) / (0.0821 L⋅atm / (mol⋅K) * 270 K)
Now, you can calculate the value of N.