Given that R= 0.0821(L⋅atm) / (mol⋅K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K?
This is what I have so far, Fill in the blank spots please.
P= 1.8 atm
V= 2L
N= ____ ?
T=270 K
PV=N= (1.8)(2)/ (0.821)(270)
RT=______ ?
PV=NRT
N = (PV) / (RT)
N = (1.8)(2) / (0.0821)(270) (plug in the given values for P, V, R, and T)
N = 0.0244 moles