A line that contains the points (0,-2) and (4,0)
The line that contains the points (0, -2) and (4, 0) can be written in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
To find the slope (m), we use the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (0, -2) and (4, 0):
m = (0 - (-2)) / (4 - 0)
m = 2 / 4
m = 1/2
Now, we need to find the y-intercept (b). We can use the slope-intercept form equation and substitute one of the points to solve for b.
Using the point (4, 0) and the slope m = 1/2:
0 = (1/2)(4) + b
0 = 2 + b
b = -2
Therefore, the equation of the line that contains the points (0, -2) and (4, 0) is:
y = 1/2 x - 2.