Question%0D%0AHow does the magnitude of the electrical charge on objects affect the electric force between them?(1 point)%0D%0AResponses%0D%0A%0D%0AAs the charge increases, the force becomes more attractive.%0D%0AAs the charge increases, the force becomes more attractive.%0D%0A%0D%0AAs the charge increases, the force becomes more negative.%0D%0AAs the charge increases, the force becomes more negative.%0D%0A%0D%0AAs the charge increases, the force increases in strength.%0D%0AAs the charge increases, the force increases in strength.%0D%0A%0D%0AAs the charge increases, the force decreases in strength.%0D%0AAs the charge increases, the force decreases in strength.
The correct response is:
- As the charge increases, the force increases in strength.
To understand why this is the case, we need to consider Coulomb's Law, which states that the electric force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically, the formula for electric force (F) is given by:
F = k * (q1 * q2) / r^2
where:
- F is the electric force between the objects,
- k is the electrostatic constant,
- q1 and q2 are the charges of the objects, and
- r is the distance between the objects.
From the formula, we can observe that as the charges (q1 and q2) increase, the force (F) also increases, assuming the distance (r) remains constant. This indicates that the magnitude of the electrical charge on objects directly affects the electric force between them.