Fn= 40n, Ff=25n, Fg= 40n, Fapplied= 60N What is the net force on this object?
a
20 N to the left
b
10 N up
c
10 N down
d
35 N to the right
To find the net force, we need to sum up all the forces acting on the object.
Given:
Fn = 40 N (force in the negative x-direction)
Ff = 25 N (force in the negative x-direction)
Fg = 40 N (force in the negative y-direction)
Fapplied = 60 N (force in the positive x-direction)
To find the net force in the x-direction, we add the forces Fn, Ff, and Fapplied:
Net force in the x-direction = Fn + Ff + Fapplied
= -40 N + (-25 N) + 60 N
= -65 N + 60 N
= -5 N
To find the net force in the y-direction, we add the force Fg:
Net force in the y-direction = Fg
= 40 N
Therefore, the net force on the object is:
a) 20 N to the left: -5 N in the x-direction and 40 N in the y-direction.
b) 10 N up: -5 N in the x-direction and 40 N in the y-direction.
c) 10 N down: -5 N in the x-direction and 40 N in the y-direction.
d) 35 N to the right: -5 N in the x-direction and 40 N in the y-direction.
Thus, the correct answer is all of the given options have a net force of -5 N in the x-direction and 40 N in the y-direction.