You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second card. Find the probability of choosing a consonant and then an “e”. There is 1 letter for each card.
A. 1/11
B. 1/121
C. 21/110
D. 2/55
Really? I see only 7 consonants.
so 7/11 * 3/10 = 21/110
So, C
Apologies for the mistake in my previous response. You are correct.
The word "replacement" has 7 consonants (R, P, L, C, M, N, T) and a total of 11 cards.
The probability of choosing a consonant first is 7/11 since there are 7 consonants out of 11 cards.
After choosing a consonant, there are 3 vowels left (E, A, E) out of a total of 10 remaining cards.
Therefore, the probability of choosing an "e" after selecting a consonant is 3/10.
To find the probability of both events occurring, we multiply the probabilities:
(7/11) * (3/10) = 21/110
Therefore, the probability of choosing a consonant and then an "e" is 21/110.
The correct answer is indeed C.
To find the probability of choosing a consonant and then an "e" from the word "replacement", we need to determine the total number of consonants and the total number of cards.
First, let's calculate the number of consonants in the word "replacement". The consonants in "replacement" are "r", "p", "l", "c", "m", and "n". So, there are 6 consonants in total.
Next, we need to determine the total number of cards. Since each card represents a letter, there are a total of 11 cards in "replacement".
To calculate the probability, we need to consider that we are choosing the cards without replacement. This means that the number of cards decreases by one each time we choose a card.
So, the probability of choosing a consonant as the first card is 6/11, since there are 6 consonants and 11 total cards.
For the second card, the probability of choosing an "e" after not replacing the first card is 1/10, since there is 1 "e" remaining and only 10 cards left.
Now, to find the probability of both events happening, we multiply the probabilities together:
(6/11) * (1/10) = 6/110
Therefore, the probability of choosing a consonant and then an "e" is 6/110, which simplifies to 3/55.
None of the provided answer choices match the calculated probability.
There are 10 consonants in the word "replacement" (R, P, L, C, M, N, T) and there are a total of 11 cards.
The probability of choosing a consonant first is 10/11 since there are 10 consonants out of 11 cards.
After choosing a consonant, there are 3 vowels left (E, A, E) out of a total of 10 cards.
Therefore, the probability of choosing an "e" after selecting a consonant is 3/10.
To find the probability of both events occurring, we multiply the probabilities:
(10/11) * (3/10) = 30/110 = 3/11
Therefore, the probability of choosing a consonant and then an "e" is 3/11.
The correct answer is not listed among the answer choices given.