We place some nitrogen and hydrogen in an empty 5.00 liter vessel at 500°C. When equilibrium is established, 3.01 mol N2, 2.10 mol H2, and 0.565 mol of NH3 are present. Calculate Keq for the following reaction at 500°C:
N2 (g) + 3H2 (g) <====== 2NH3(g)
The balanced equation for the reaction is:
N2 (g) + 3H2 (g) ⇌ 2NH3(g)
To calculate Keq, we need to use the concentrations of the reactants and products at equilibrium.
The initial volume of the vessel is 5.00 L.
The concentration of N2 at equilibrium is 3.01 mol / 5.00 L = 0.602 mol/L.
The concentration of H2 at equilibrium is 2.10 mol / 5.00 L = 0.420 mol/L.
The concentration of NH3 at equilibrium is 0.565 mol / 5.00 L = 0.113 mol/L.
Now, we can plug these values into the expression for Keq:
Keq = [NH3]^2 / ([N2] * [H2]^3)
Keq = (0.113 mol/L)^2 / ((0.602 mol/L) * (0.420 mol/L)^3)
Keq ≈ 0.026