a mountain goat is climbing to the top of a large cliff. the cliff is 50 feet higher than its starting point. if it takes the goat 22 mins to climb this cliff, interpret the quotient to describe the rate of changing in the goats elevation. give your answer to the nearest hundredth.(1 point)
The quotient to describe the rate of changing in the goat's elevation is the change in elevation divided by the time it took.
In this case, the change in elevation is 50 feet and the time it took for the goat to climb the cliff is 22 minutes.
So the rate of changing in the goat's elevation is 50 feet / 22 minutes = 2.27 feet/minute.
Therefore, the quotient describes that the goat's elevation is changing by 2.27 feet per minute.
a bird is flying at an average altitude of 10 meters above the ground. after 3 seconds, it settles on a branch that is 3 meters above ground. interpret the quotient to describe the rate of change in the birds altitude. give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient to describe the rate of change in the bird's altitude is the change in altitude divided by the time it took.
In this case, the change in altitude is from 10 meters above the ground to 3 meters above the ground, which is a descent of 7 meters. The time it took for the bird to descend is 3 seconds.
So the rate of change in the bird's altitude is 7 meters / 3 seconds = 2.33 meters/second.
Therefore, the quotient describes that the bird's altitude is changing by 2.33 meters per second as it descends.
a bird is flying at an average altitude of 10 meters above the ground. after 3 seconds, it settles on a branch that is 3 meters above the ground. interpret the quotient describing the rate of change in the birds altitude. give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
Apologies for the confusion in my previous response.
To find the rate of change in the bird's altitude, we need to calculate the change in altitude divided by the time it took.
The initial altitude of the bird is 10 meters above the ground, and it settles on a branch that is 3 meters above the ground. Therefore, the change in altitude is 10 meters - 3 meters = 7 meters.
The time it took for the bird to descend is given as 3 seconds.
So, the rate of change in the bird's altitude is 7 meters / 3 seconds = 2.33 meters/second.
Therefore, the quotient describes that the bird's altitude is changing by 2.33 meters per second as it descends.
a whale is swimming at a current depth of 15 meters below the surface. it swims up toward the surface and arrives there 9.5 seconds later. find the quotient that best describes the rate of changing in the whales depth. give your answer to the nearest hundredth.(1 point)
To find the quotient that describes the rate of change in the whale's depth, we need to calculate the change in depth divided by the time it took.
The initial depth of the whale is 15 meters below the surface, and it swims up to the surface. Therefore, the change in depth is 15 meters + 0 meters (since it reaches the surface) = 15 meters.
The time it took for the whale to reach the surface is given as 9.5 seconds.
So, the rate of change in the whale's depth is 15 meters / 9.5 seconds = 1.58 meters/second.
Therefore, the quotient describes that the whale's depth is changing at a rate of 1.58 meters per second as it swims up towards the surface.
solve using long division of rational numbers. if a car value decreases by $2,500 in the first 6 months, how much does the value decrease per month?(round to the nearest hundredth.)(1 point)
To find the value decrease per month, we need to divide the total decrease by the number of months.
The total decrease in value is $2,500 and the time period is 6 months.
To perform long division, we divide $2,500 by 6:
416.67
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6 | 2,500.00
- 2,496.00
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4.00
So, the value decreases by $416.67 per month.
Therefore, the value of the car decreases by $416.67 per month.