given l = 30 in., w = 20 in., h = 18 in., and x - 36.1 in., find the length of d. round the answer to the nearest tenth
We do not have enough information to find the length of d. Could you please provide additional information?
i cant.
i said the length is 30 in. the width is 20 in. the height is 18 in. and x= 36.1 inches
Apologies for the confusion. Let's assume that d is a variable representing an unknown length.
Given:
l = 30 in
w = 20 in
h = 18 in
x = 36.1 in
To find the length of d, we can use the Pythagorean theorem. The formula is:
d = sqrt(l^2 + w^2 + h^2)
Substituting the given values:
d = sqrt(30^2 + 20^2 + 18^2)
d = sqrt(900 + 400 + 324)
d = sqrt(1624)
d ≈ 40.3 inches
Therefore, the length of d is approximately 40.3 inches.
ty!
now, find the length of the height of the cone
d = 10 cm and the slant height is 13 cm
To find the length of the height of the cone, we'll need to use the Pythagorean theorem.
Given:
diameter (d) = 10 cm
slant height = 13 cm
The slant height (s), height (h), and radius (r) of a cone form a right triangle. The formula is:
s^2 = r^2 + h^2
Since the diameter is twice the radius, we have r = d/2.
Substituting the given values:
13^2 = (10/2)^2 + h^2
169 = 25 + h^2
h^2 = 169 - 25
h^2 = 144
Taking the square root of both sides:
h = √144
h = 12 cm
Therefore, the length of the height of the cone is 12 cm.
for the square pyramid, the lateral edge length, 'e', is 25 inches, and the slant height, 's', is 24 inches. find the height of the pyramid, 'h'. round the answer to the nearest whole number.
HINT: before finding the length of 'h', you will first need to find the length of 'r'.
To find the height of the square pyramid, we'll start by finding the length of the base diagonal (r) using the Pythagorean theorem.
Given:
lateral edge length (e) = 25 inches
slant height (s) = 24 inches
The base diagonal (r), half the length of the base side (s/2), and the slant height (s) of a square pyramid form a right triangle. The formula is:
r^2 = (s/2)^2 + e^2
Substituting the given values:
r^2 = (24/2)^2 + 25^2
r^2 = 12^2 + 625
r^2 = 144 + 625
r^2 = 769
Taking the square root of both sides:
r ≈ √769
r ≈ 27.7 inches
Now that we have the length of the base diagonal (r), we can find the height (h) of the pyramid using the Pythagorean theorem.
h^2 = s^2 - (r/2)^2
h^2 = 24^2 - (27.7/2)^2
h^2 = 576 - (13.85)^2
h^2 = 576 - 191.7225
h^2 ≈ 384.2775
Taking the square root of both sides:
h ≈ √384.2775
h ≈ 19.6 inches
Rounding to the nearest whole number, the height of the pyramid, h, is approximately 20 inches.
that's incorrect
Apologies for the mistake. Let's go through the calculation again.
Given:
Lateral edge length (e) = 25 inches
Slant height (s) = 24 inches
To find the height (h) of the pyramid, we'll first find the length of the base diagonal (r) using the Pythagorean theorem.
r^2 = (s/2)^2 + e^2
Substituting the given values:
r^2 = (24/2)^2 + 25^2
r^2 = 12^2 + 625
r^2 = 144 + 625
r^2 = 769
r ≈ √769
r ≈ 27.7 inches
Now that we have the base diagonal (r), we can find the height (h) using another right triangle formed by the height, half the length of the base side (s/2), and r.
h^2 = r^2 - (s/2)^2
h^2 = 27.7^2 - (24/2)^2
h^2 = 767.29 - 12^2
h^2 ≈ 767.29 - 144
h^2 ≈ 623.29
h ≈ √623.29
h ≈ 24.95 inches
Rounding to the nearest whole number, the height of the pyramid (h) is 25 inches.
Therefore, the correct answer is that the height of the pyramid is approximately 25 inches.