Which of the following is a point on the graph as described by
the function y = (2x + 1) ^2 - 4
?
To find a point on the graph, we can substitute a value for x into the equation and solve for y. Let's try substituting x = 0.
y = (2(0) + 1) ^2 - 4
y = (1) ^2 - 4
y = 1 - 4
y = -3
So, (0, -3) is a point on the graph.
Which of the following is a point on the graph as described by
the function y = (2x + 1)2-4
?
To find a point on the graph, we need to substitute values for x into the equation and find the corresponding y-values.
The given equation is y = (2x + 1)^2 - 4.
Let's substitute x = 0 into the equation:
y = (2(0) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3
So, when x = 0, y = -3.
Therefore, the point on the graph is (0, -3).
To find a point on the graph described by the function y = (2x + 1) ^2 - 4, we can choose a value for x and substitute it into the equation to solve for y. Let's choose a value for x and find the corresponding y-coordinate.
Let's say we choose x = 0 as our value.
Substituting x = 0 into the equation, we have:
y = (2(0) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3
Therefore, when x = 0, y = -3.
So, the point (0, -3) is on the graph described by the function y = (2x + 1) ^2 - 4.