suppose that an object is dropped from a height of h meters abd hits the ground with a velocity of v meters per second. then v=√19.6h . if an object hits the ground with a velocity of 17.4 meters per second, from what height was it dropped?
To find the height from which the object was dropped, we can use the formula v = √(2gh), where v is the final velocity, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height.
Given that v = 17.4 m/s, we can substitute the values into the formula:
17.4 = √(2 * 9.8 * h)
Squaring both sides of the equation:
17.4² = 2 * 9.8 * h
302.76 = 19.6 * h
Dividing both sides of the equation by 19.6:
h = 302.76 / 19.6
h ≈ 15.46 meters
Therefore, the object was dropped from a height of approximately 15.46 meters.