Given that the a.p is 7 and it's 10th term is twice the second term find the difference between 9th &6th term
Let the second term of the arithmetic progression be x.
The 2nd term is x.
The 10th term is 2x.
The common difference is the difference between any two consecutive terms in the arithmetic progression. In this case, the common difference is given by the formula: common difference = (10th term - 2nd term) / (10 - 2) = (2x - x) / 8 = x/8.
The 6th term of the arithmetic progression is given by: 2nd term + (6 - 2) * common difference = x + 4 * (x/8) = 2x.
The difference between the 9th and 6th term is: 9th term - 6th term = (2x + 8 * (x/8)) - 2x = 2x + x - 2x = x.
Therefore, the difference between the 9th and 6th term is x.