A circle has the equation 16x^2+16y^2=256. What are the coordinates for the centre of the circle?
The general equation for a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) represents the coordinates of the center and r represents the radius.
Comparing this general equation with the given equation, we can see that the given equation is already in standard form. Therefore, the coordinates of the center of the circle are (0, 0).
A circle has the equation 16x^2+16y^2=256. What are the coordinates for the centre of the circle? State the radius of the circle.
To find the center and radius of the circle, we need to rewrite the equation in standard form, which is typically expressed as:
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 256:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the center is (0, 0) and the radius is √16 = 4.
A circle has the equation 16x^2+16y^2=256.
State the radius of the circle.
To find the radius of the circle, we need to rewrite the equation in standard form, which is typically expressed as:
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 16, we get:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the radius of the circle is √16 = 4.
To find the coordinates for the center of the circle, we can start by rearranging the equation of the circle to its standard form, which is (x - h)^2 + (y - k)^2 = r^2.
Given equation: 16x^2 + 16y^2 = 256
Start by dividing all terms by 256 to simplify the equation:
x^2 + y^2 = 16
Now, compare this equation to the standard form:
(x - h)^2 + (y - k)^2 = r^2
We can see that h = 0, k = 0, and r^2 = 16.
So, the coordinates of the center of the circle are (h, k) = (0, 0).