Calculate the temperature of 1 mole of oxygen gas collected in a 10 L container at 1 atm of pressure given the gas constant R = 0.0821 Latm/molK. (2 pts)
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2 points
0.821 K
821 K
244 K
122 K
To find the temperature, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure = 1 atm
V = volume = 10 L
n = number of moles = 1 mole
R = gas constant = 0.0821 Latm/molK
T = temperature (in Kelvin)
Rearranging the equation to solve for T:
T = PV / (nR)
Substituting the given values:
T = (1 atm * 10 L) / (1 mole * 0.0821 Latm/molK)
T = 10 / 0.0821
T ≈ 121.67 K
Therefore, the temperature of 1 mole of oxygen gas collected in a 10 L container at 1 atm of pressure is approximately 121.67 K. rounded to 122 K.