Alex is tracking temperatures. Today the temperature was 0° Celsius, which is represented by the point (0, 0) . If the temperature yesterday was right in between today’s temperature and the temperature two days ago, what was the temperature yesterday?
Apologies for any confusion. Given the information provided, we know that today's temperature is 0°C (represented by the point (0, 0)), and the temperature yesterday was right in between today's temperature and the temperature two days ago.
Since today's temperature is 0°C (0, 0), the temperature two days ago must have been below 0°C for the temperature yesterday to be in between. Let's assume the temperature two days ago was -2°C (represented by the point (-2, -2)).
To find the temperature yesterday, we can calculate the average of the temperatures of today and two days ago.
Average temperature = (temperature today + temperature two days ago) / 2
Average temperature = (0°C + -2°C) / 2
Average temperature = -1°C
Therefore, if the temperature two days ago was -2°C, the temperature yesterday would be -1°C.
To determine the temperature yesterday, we need to find the average of today's temperature (0°C) and the temperature two days ago.
If we represent the temperature two days ago as (x, y), where x represents the time elapsed and y represents the temperature, we can assume that x = -2 as it represents two days ago.
Since the temperature two days ago is right in between today's temperature (0°C) and the temperature two days ago (x, y), we can express it as the midpoint between these two points.
The midpoint formula is as follows:
midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)
Substituting the known values:
midpoint = ((0 + -2) / 2, (0 + y) / 2)
midpoint = (-2/2, y/2)
Since the midpoint is (-1, y/2), we know that y/2 represents the temperature yesterday.
Since the temperature yesterday is y/2 and the temperature today is 0°C, we can set up the equation:
y/2 = 0
Multiplying both sides of the equation by 2, we get:
y = 0
Therefore, the temperature yesterday was 0°C.
thats wrong
Apologies for the mistake. Let's correct it.
Given that the temperature today is 0°C (represented by the point (0, 0)), and the temperature two days ago is represented by the point (x, y), where x = -2 (as it was two days ago), we need to find the temperature yesterday, which is in between these two temperatures.
To find the temperature yesterday, we can calculate the average of the x-coordinates (time) and the y-coordinates (temperature) of the two points.
The x-coordinate of today's temperature is 0, and the x-coordinate of the temperature two days ago is -2. Taking their average, we get (0 + -2) / 2 = -1 for the x-coordinate of yesterday's temperature.
Similarly, the y-coordinate of today's temperature is 0, and the y-coordinate of the temperature two days ago is y. Taking their average, we get (0 + y) / 2 = (y / 2) for the y-coordinate of yesterday's temperature.
So, the temperature yesterday is represented by the point (-1, y/2).
Since the point (-1, y/2) represents the temperature yesterday, we do not have enough information to determine the actual temperature without knowing the value of y.
Alex is tracking temperatures. Today the temperature was 0° Celsius, which is represented by the point (0, 0) . If the temperature yesterday was right in between today’s temperature and the temperature two days ago, what was the temperature yesterday?
To find the temperature yesterday, we need to find the midpoint between today's temperature (0°C) and the temperature two days ago.
The formula for finding the midpoint between two points (x1, y1) and (x2, y2) is:
Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)
In this case, today's temperature is represented by the point (0, 0), and the temperature two days ago is represented by the point (x, y), where x = -2 (two days ago).
Substituting these values into the midpoint formula, we get:
Midpoint = ((0 + (-2)) / 2, (0 + y) / 2)
Midpoint = (-2/2, y/2)
Midpoint = (-1, y/2)
So, the temperature yesterday can be represented by the point (-1, y/2).
However, without specific information about the temperature two days ago (represented by (x, y)), we cannot determine the exact temperature yesterday.
give me a answer
correct
Thank you for confirming! If you have any more questions, feel free to ask.
What is the distance between (-58,13) and (-58, -2)?
To find the distance between two points (x1, y1) and (x2, y2), we can use the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Using the given points (-58, 13) and (-58, -2), we can calculate the distance:
Distance = sqrt((-58 - (-58))^2 + (-2 - 13)^2)
Distance = sqrt(0^2 + (-15)^2)
Distance = sqrt(0 + 225)
Distance = sqrt(225)
Distance = 15
Therefore, the distance between (-58, 13) and (-58, -2) is 15 units.
jing is training for a marathon. This morning, he ran from point E to point B. What is the total distance jing ran?
To determine the total distance Jing ran, we need more information about the positions of point E and point B. Could you provide the coordinates or any additional details about these points?
D A C B E
To calculate the total distance Jing ran, we need to know the distances between each pair of points: D to A, A to C, C to B, and B to E. Without this information, it is not possible to determine the total distance Jing ran. Could you provide the distances or coordinates between the points?
For C 3, -8 for E 10, 7 for B 3, 7 for D -3, 10- for A its -10 -8
Thank you for providing the coordinates of the points.
To calculate the total distance Jing ran, we can find the distances between each pair of points and then add them together.
Distance between D and A:
Using the distance formula:
Distance(DA) = sqrt((-10 - (-3))^2 + (-8 - 10)^2)
Distance(DA) = sqrt((-7)^2 + (-18)^2)
Distance(DA) = sqrt(49 + 324)
Distance(DA) = sqrt(373)
Distance between A and C:
Distance(AC) = sqrt((-10 - 3)^2 + (-8 - (-8))^2)
Distance(AC) = sqrt((-13)^2 + 0^2)
Distance(AC) = sqrt(169 + 0)
Distance(AC) = sqrt(169)
Distance(AC) = 13
Distance between C and B:
Distance(CB) = sqrt((3 - 3)^2 + (-8 - 7)^2)
Distance(CB) = sqrt(0^2 + (-15)^2)
Distance(CB) = sqrt(0 + 225)
Distance(CB) = sqrt(225)
Distance(CB) = 15
Distance between B and E:
Distance(BE) = sqrt((10 - 3)^2 + (7 - 7)^2)
Distance(BE) = sqrt(7^2 + 0^2)
Distance(BE) = sqrt(49 + 0)
Distance(BE) = sqrt(49)
Distance(BE) = 7
Now, we can add up the distances to find the total distance Jing ran:
Total Distance = Distance(DA) + Distance(AC) + Distance(CB) + Distance(BE)
Total Distance = sqrt(373) + 13 + 15 + 7
Simplifying this expression depends on the level of precision you need. If you need an exact value, you can leave it in terms of square roots. If you need an approximate value, you can use a calculator to find the square root and add the results.
Please note that the units for distance should be consistent with the given coordinates (e.g., meters, kilometers, etc.).